Respuesta :
Since the hiker can move in any direction, the equation that represent the area in which the hiker could be will be the equation of circle with radius r=12 and center (5,10)
The equation of a circle with radius r and center (h,k) is:
[tex](h-x) ^{2} +(y-k) ^{2} =r ^{2} [/tex]
The only thing we have left is replace the values to get:
[tex](x-5) ^{2} +(y-10) ^{2} =12 ^{2} [/tex]
[tex](x-5) ^{2} +(y-10) ^{2} =144[/tex]
The equation of a circle with radius r and center (h,k) is:
[tex](h-x) ^{2} +(y-k) ^{2} =r ^{2} [/tex]
The only thing we have left is replace the values to get:
[tex](x-5) ^{2} +(y-10) ^{2} =12 ^{2} [/tex]
[tex](x-5) ^{2} +(y-10) ^{2} =144[/tex]
Answer: The circle in the problem takes the form (x-h)^2+ (y-k)^2. The hiker started at the center of the circle (h,k)=(5,10). The radius of the circle = 12. When you plug these values into the equation, you get (x-5)^2+ (y-10)^2=12^2