find the first, fourth, and eighth terms of the sequence a(n)= -3*2^n-1
A.)1; -216;-279936
B.)-12; -96; -1536
C.)-3; -24; -384
D.)-6; -48 ; -768

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Snoop5133 Snoop5133 · Answer 1 · 2018-10-11T23:18:11+02:00

The correct answer is c.

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jainveenamrata jainveenamrata · Answer 2 · 2022-08-12T14:53:08+02:00

The first, fourth, and eighth terms of the geometric sequence will be -3, -24, and -384. Then the correct option is C.

Let a₁ be the first term and r be the common ratio.

Then the nth term of the geometric sequence is given as,

aₙ = a₁ · (r)ⁿ⁻¹

The first term is negative 3 and the common ratio is 2.

Then the expression is given as,

aₙ = -3 · (2)ⁿ⁻¹

The first value of the sequence will be negative 3.

The fourth value of the sequence will be

a₄ = -3 · (2)⁴⁻¹

a₄ = -3 · 8

a₄ = -24

The eighth value of the sequence will be

a₈ = -3 · (2)⁸⁻¹

a₈ = -3 · 128

a₈ = -384

Then the first, fourth, and eighth terms of the geometric sequence will be -3, -24, and -384.

Then the correct option is C.

More about the geometric sequence link is given below.

https://brainly.com/question/11266123

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