Answer:
9.67 years.
Explanation:
The way you solve for the orbital period of a planet is by using the equation P^2 = a^3. P is equal to the orbital planet while a is equal to AU. To solve this problem, we begin by replacing a with 4.54 since we already have that information. Then, we multiply it by an exponent of three. We get the answer 93.576664, or 93.58. To make both sides even, we square root the answer so that the exponent over the P does not remain. We get the solution of 9.67350319, or 9.67. In the end, the above planet's orbital period is about 9.67 years.
A planet has an average distance to the sun of 4.54 AU is 9.67 years.
The way you solve for the orbital period of a planet is by using the equation P^2 = a^3.
P is equal to the orbital planet while a is equal to AU. To solve this problem, we begin by replacing a with 4.54 since we already have that information.
Then, we multiply it by an exponent of three. We get the answer 93.576664, or 93.58. To make both sides even, we square root the answer so that the exponent over the P does not remain. We get the solution of 9.67350319, or 9.67. In the end, the above planet's orbital period is about 9.67 years.
Thus, 9.67 years is the answer.
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