PLEASE ANSWER ASAP!!!!!!!!!!!!!!!

The perimeter of a rectangle is at most 80 inches. The length of the rectangle is 25 inches. The inequality 80 - 2w > 50 can be used to find w, the width of the rectangle in inches. Solve the inequality and interpret the solution. How will the solution change in the width must be at least 10 inches and a whole number?

Respuesta :

W=15 Subtract 80 from both sides then you divide by -2w.

Answer:

(1). The solution of inequality is 15>w. It means the width of the rectangle is less than 15 inches.

(2) The solution set is w={10,11,12,13,14}.

Step-by-step explanation:

The given inequality is

[tex]80-2w>50[/tex]

where, w is the width of the rectangle in inches.

Add 2w on both sides.

[tex]80-2w+2w>50+2w[/tex]

[tex]80>50+2w[/tex]

Subtract 50 from both sides.

[tex]80-50>50+2w-50[/tex]

[tex]30>2w[/tex]

Divide both sides by 2.

[tex]\frac{30}{2}>w[/tex]

[tex]15>w[/tex]          ... (1)

The solution of inequality is 15>w. It means the width of the rectangle is less than 15 inches.

The width must be at least 10 inches and a whole number.

[tex]10\leq w[/tex]           .... (2)

Using (1) and (2), we get

[tex]10\leq w<15[/tex]

[tex]w=\{10,11,12,13,14\}[/tex]

Therefore the solution set is w={10,11,12,13,14}.