Respuesta :
Hello HayFieldSynus,
I believe the answer is Chris had sold 7 cups of lemonade when the challenge started at noon. As far as I can see, there aren't any more. I may be wrong. I am sorry I don't have another answer. Hopefully, this will help you. Have a good day!
Pepperdog
I believe the answer is Chris had sold 7 cups of lemonade when the challenge started at noon. As far as I can see, there aren't any more. I may be wrong. I am sorry I don't have another answer. Hopefully, this will help you. Have a good day!
Pepperdog
Answer:
The correct options are 2 and 3.
Step-by-step explanation:
The table shows the total number of cups of lemonade Chris sold at the end of each remaining hour of his sale.
The function passing through the points (0,7) and (1,10).
The equation of the function is
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-7=\frac{10-7}{1-0}(x-0)[/tex]
[tex]y=3x+7[/tex] .....(1)
The number of cups of lemonade Bethany sold for the remaining hours of her sale is
[tex]y=4x+5[/tex] .... (2)
Where, y representing the number of cups sold and x representing the time in hours.
The slope intercept of a function is
[tex]y=mx+b[/tex]
Where, m is slope and b s y-intercept.
The slope of Chris function is 3 and the y-intercept is 7. The slope of Bethany function is 4 and the y-intercept is 5.
It means beginning at noon Chris sold 3 cups of lemonade each hour. Option 1 is incorrect.
Chris had sold 7 cups of lemonade when the challenge started at noon. Option 2 is correct.
It means beginning at noon Bethany sold 4 cups of lemonade each hour. Option 3 is correct.
Since 7>5, therefore Chris sold more cups of lemonade than Bethany at noon. Option 4 is incorrect.