[tex]\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\\
\end{cases}\\\\
-------------------------------\\\\
P(x)=3.113(1.2795)^x\implies \stackrel{A}{P(x)}=\stackrel{I}{3.113}(1+\stackrel{r}{0.2795})^{\stackrel{t}{x}}[/tex]
usually, the "r" above, is used as a "rate of increase".
but 1+r combined, can be referred as the "rate for the new size".
so, for example, if something is increasing at a rate of 25%, 1+0.25 or 1.25, the new size wil be 1.25 or 125% of the old size.
