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When one atom of hydrogen (H) combines with one atom of bromine (Br), their bonding results in a molecule of HBr. Which of the following describes the arrangement of valence electrons in a bond between H and Br?

The valence electrons are shared equally between H and Br.
The valence electrons spend more time around the atom of H.
The valence electrons spend more time around the atom of Br.
The valence electrons are given up by the H and gained by the Br.

Respuesta :

HBr is considered to be an ionic compound

So here Hydrogen loses its electron and this electron is being gained by bromine atom

In this process Hydrogen becomes positively charged while bromine becomes negatively charged

The two charges are attracted by electrostatic attractions

Thus the correct answer is

The valence electrons are given up by the H and gained by the Br.


Answer: The valence electrons spend more time around the atom of Br.

Explanation:

Covalent compound is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound. These are usually formed when two non-metals react.

Polar covalent compound is defined as the compound which is formed when difference in electronegativity between the atoms is present. When atoms of different elements combine, it results in the formation of polar covalent bond. For Example: [tex]CO_2,NO_2[/tex] etc..

In the given chemical compound HBr, bromine is more electronegative and hydrogen is less electronegative.

So, the valence electrons will be more towards bromine atom in the given compound.

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