contestada

What is the value of x?

Round to the nearest tenth, if necessary.

x = 6

x = 11

x = 11.5

x = 13.6

What is the value of x Round to the nearest tenth if necessary x 6 x 11 x 115 x 136 class=

Respuesta :

theandysanchez
A^2+B^2=c^2 for a right triangle
In this case x is a, b is 8 and c is 14 plug in
X^2= 14^2-8^2
X^2=132
X=11.48
X=11.5
kudzordzifrancis
ANSWER

[tex]x = 11.5[/tex]
EXPLANATION

Triangle ABC is a right angle triangle.

We can apply the Pythagorean Theorem to get,

[tex] {x}^{2} + {8}^{2} = {14}^{2} [/tex]

We now solve for x to get,

[tex] {x}^{2} = {14}^{2} - {8}^{2}[/tex]
The right hand side is difference of two squares, this factors to give us,

[tex] {x}^{2} = (14 - 8)(14 + 8)[/tex]

[tex] {x}^{2} = 6 \times 22[/tex]

[tex] {x}^{2} = 132[/tex]

We take the positive square root of both sides to obtain,

[tex]x = \sqrt{132} [/tex]

[tex]x = 11.48[/tex]

[tex]x = 11.5[/tex]

Otras preguntas