A carousel is moving with uniform circular motion. The centripetal acceleration of the ride is * 1 point circular
. perpendicular to the plane of motion.
zero.
directed toward the center of motion.
Where should a force be applied on a lever arm to produce the most torque? * 1 point closest to the axis of rotation farthest from the axis of rotation in the middle of the lever arm it does not matter where the force is applied A boy can raise a rock that weighs 120 N by using a lever and applying a force of 25 N.
What is the mechanical advantage of the lever? * 1 point .21 3.5 4.8 225 A pebble that is 3.81 m from the eye of a tornado has a tangential speed of 124 m/s. What is the magnitude of the pebble's centripetal acceleration? * 2 points 32 m/s² 85 m/s² 435 m/s² 4036 m/s² A dog sits 1.25 m from the center of a merry go round and revolves at a tangential speed of 2.0 m/s. If the dog's mass is 19.3 kg, what is the magnitude of the centripetal force on the dog? * 2 points 103 N 40. N 61.8 N 21.3 N A ball attached to a string is whirled in a circle. If the string breaks, what causes the ball to move in a straight line? * 1 point inertia centripetal acceleration centrifugal force centripetal force Find the magnitude of the gravitational force exerted on a 66.5 kg astronaut on the surface of Planet X if the planet has a radius of 4.40 x 10⁶ m and a mass of 8.43 x 10²³ kg.(Use G= 6.67 x 10⁻¹¹ Nm/kg²) * 2 points 193 N 246 N 38.5 N 651 N How would the speed of the Earth's orbit change if the Earth's distance from the Sun increased by 9 times? * 1 point Increase by a factor of 3 Increase by a factor of 9 Decrease by a factor of one third Decrease by a factor of 3 What is the efficiency of a crane that requires 28,000 J of energy to lift a 200 kg object 10 meters? * 2 points 15% 34% 60% 70% What is the force required to produce a 1.4 Nm torque when applied to a door at a 60.0º angle and 0.40 m from the hinge? * 2 points 2.0 N 4.0 N 5.7 N 8.2 N

Respuesta :

> A carousel is moving with uniform circular motion. The centripetal acceleration of the ride is:

Centripetal acceleration is always directed  toward the center of motion

 

> Where should a force be applied on a lever arm to produce the most torque?

farthest from the axis of rotation

 

> A boy can raise a rock that weighs 120 N by using a lever and applying a force of 25 N.

What is the mechanical advantage of the lever?

Simply divide the weight by the force applied:

120 / 25 = 4.8

 

> A pebble that is 3.81 m from the eye of a tornado has a tangential speed of 124 m/s. What is the magnitude of the pebble's centripetal acceleration?

Centripetal acceleration is calculated using the formula:

a = v^2 / r

a = (124 m/s)^2 / 3.81 m

a = 4,035.70 m/s^2 ~ 4036

 

> A dog sits 1.25 m from the center of a merry go round and revolves at a tangential speed of 2.0 m/s. If the dog's mass is 19.3 kg, what is the magnitude of the centripetal force on the dog?

a = v^2 / r

a = (2.0 m/s)^2 / 1.25 m

a = 3.2 m/s^2

 

The force is:

F = m a

F = 19.3 kg * 3.2 m/s^2

F = 61.8 N

 

> A ball attached to a string is whirled in a circle. If the string breaks, what causes the ball to move in a straight line?

The force which is directed away from the center of the motion: centrifugal force

 

> Find the magnitude of the gravitational force exerted on a 66.5 kg astronaut on the surface of Planet X if the planet has a radius of 4.40 x 10⁶ m and a mass of 8.43 x 10²³ kg.(Use G= 6.67 x 10⁻¹¹ Nm/kg²)

We use the formula:

F = G m1 m2 / r^2

F = 6.67 x 10⁻¹¹ Nm/kg² * (66.5 kg) * (8.43 x 10²³ kg) / (4.40 x 10⁶ m)^2

F = 193 N

 

> How would the speed of the Earth's orbit change if the Earth's distance from the Sun increased by 9 times?

The orbital speed is related to distance from the formula:

v = sqrt (GM / r)

where r is the distance from Earth to Sun

so if r’ = 9 r

v = sqrt (GM / 9r)

v = (1/3) sqrt (GM / r)

Therefore: Decrease by a factor of 3

 

> What is the efficiency of a crane that requires 28,000 J of energy to lift a 200 kg object 10 meters?

The total work done is:

Work = 200 kg * 9.8 m/s^2 * 10 m

Work = 19,600 J

 

So efficiency is:

efficiency = 19,600 / 28,000 * 100% = 70%

 

> What is the force required to produce a 1.4 Nm torque when applied to a door at a 60.0º angle and 0.40 m from the hinge?

The perpendicular component of the applied force is:

F * sin(60°) = 0.866F N

Since the moment arm is 0.40 m, the torque is:

(0.866F N)*(0.4 m) = 0.3464F N-m

This torque is equal to a value of 1.4 N-m, therefore

0.3464F = 1.4

F = 4.0 N