Respuesta :
Air resistance is ignored.
g = 9.8 m/s².
At maximum height, the vertical velocity is zero.
Let h = the maximum height reached.
Let u = the vertical launch velocity.
Because ot takes 5.0 seconds to reach maximum height, therefore
(u m/s) - (9.8 m/s²)*(5 s) = 0
u = 49 m/s
The maximum height reached is
h = (49 m/s)*(5 s) - (1/2)*(9.8 m/s²)*(5 s)²
= 122.5 m
Answer: 122.5 m
g = 9.8 m/s².
At maximum height, the vertical velocity is zero.
Let h = the maximum height reached.
Let u = the vertical launch velocity.
Because ot takes 5.0 seconds to reach maximum height, therefore
(u m/s) - (9.8 m/s²)*(5 s) = 0
u = 49 m/s
The maximum height reached is
h = (49 m/s)*(5 s) - (1/2)*(9.8 m/s²)*(5 s)²
= 122.5 m
Answer: 122.5 m
The maximum height reached by the rocket is 122.5 m.
The given parameters;
- time of motion of the t = 5.0 s
The maximum height of the model rocket is calculated by applying second equation of motion;
h = v₀t + ¹/₂gt²
where;
- v₀ is the initial velocity at the maximum height before the rocket starts moving downwards;
- g is acceleration due to gravity = 9.8 m/s²
h = 0 + (0.5 x 9.8 x 5²)
h = 122.5 m
Thus, the maximum height reached by the rocket is 122.5 m.
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