Respuesta :
Solve for y in −4+4y+5z=7
Substitute y=\frac{11-5z}{4}y=411−5z into -x-y-z=-8−x−y−z=−8
−x−4\frac{11−5z}{4}−z=−8
Substitute y=\frac{11-5z}{4}y=411−5z into 2x+2z=42x+2z=4
2x+2z=4
Solve for x in -x-\frac{11-5z}{4}-z=-8−x−411−5z−z=−8
x=−4\frac{11−5z}{4}+8−z
Substitute x=-\frac{11-5z}{4}+8-zx=−4\frac{11−5z}{4}+8−z into y=\frac{11-5z}{4}y=4
y=4 \frac{11−5z}
Substitute x=-\frac{11-5z}{4}+8-zx=−4 \frac{11−5z}{4}+8−z into 2x+2z=42x+2z=4
\frac{5z−11}{2}+16=4
Solve for z in \frac{5z-11}{2}+16=425z−11+16=4
z=\frac{-13}{-5}
Substitute z=-\frac{13}{5}z=−513 into x=-\frac{11-5z}{4}+8-zx=−411−5z+8−z
x=\frac{23}{5}
Substitute z=-\frac{13}{5}z=−513 into y=\frac{11-5z}{4}y=411−5z
y=6
Substitute y=\frac{11-5z}{4}y=411−5z into -x-y-z=-8−x−y−z=−8
−x−4\frac{11−5z}{4}−z=−8
Substitute y=\frac{11-5z}{4}y=411−5z into 2x+2z=42x+2z=4
2x+2z=4
Solve for x in -x-\frac{11-5z}{4}-z=-8−x−411−5z−z=−8
x=−4\frac{11−5z}{4}+8−z
Substitute x=-\frac{11-5z}{4}+8-zx=−4\frac{11−5z}{4}+8−z into y=\frac{11-5z}{4}y=4
y=4 \frac{11−5z}
Substitute x=-\frac{11-5z}{4}+8-zx=−4 \frac{11−5z}{4}+8−z into 2x+2z=42x+2z=4
\frac{5z−11}{2}+16=4
Solve for z in \frac{5z-11}{2}+16=425z−11+16=4
z=\frac{-13}{-5}
Substitute z=-\frac{13}{5}z=−513 into x=-\frac{11-5z}{4}+8-zx=−411−5z+8−z
x=\frac{23}{5}
Substitute z=-\frac{13}{5}z=−513 into y=\frac{11-5z}{4}y=411−5z
y=6