Respuesta :
Consider the value of f at x=2.
f(2)=5*2+15=10+15=25. Thus, we have the point (2, 25) in the graph of f.
The graph of g is the graph of f compressed horizontally by a factor of 1/5.
So at 2, the y-coordinate is 25(1/5=5). That is, we have the point (2, 5).
All pairs (x, y) in f can be described by (x, 5x+15), thus, all pairs (x, y) in g can be described by (x, (5x+15)/5), that is (x, x+3). Thus, the rule for g is :
g(x)=x+3.
Answer: A) g(x)=x+3
f(2)=5*2+15=10+15=25. Thus, we have the point (2, 25) in the graph of f.
The graph of g is the graph of f compressed horizontally by a factor of 1/5.
So at 2, the y-coordinate is 25(1/5=5). That is, we have the point (2, 5).
All pairs (x, y) in f can be described by (x, 5x+15), thus, all pairs (x, y) in g can be described by (x, (5x+15)/5), that is (x, x+3). Thus, the rule for g is :
g(x)=x+3.
Answer: A) g(x)=x+3
the answer is actually g(x)=25x+15 just took the test btw are you in k12?