Answer:
The complex number 6(cos 330° + i sin 330°) in the form of a+bi is:
3√3-3 i
Step-by-step explanation:
6(cos 330° + i sin 330°)
= 6(cos(360°-30°)+ i sin(360°-30°))
=6(cos30°- i sin30°) (since, 360°-30° lies in fourth quadrant and cos is positive there and sin is negative)
=[tex]6(\dfrac{\sqrt{3}}{2}-i\dfrac{1}{2})[/tex]
Distributing 6, we get
=3√3-3 i
Hence, the complex number 6(cos 330° + i sin 330°) in the form of a+bi is:
3√3-3 i
