f(x) = 2x^2 + 3 and g(x) = x^2 - 7, find (f-g)(x)

A) 3x^2 - 10
B) x^2 - 4
C) x^2 + 10
D) 3x^2 - 4

Let's solve for a.y=2x2+3andgxStep 1: Flip the equation.3adgnx+2x2=yStep 2: Add -2x^2 to both sides.3adgnx+2x2+−2x2=y+−2x23adgnx=−2x2+yStep 3: Divide both sides by 3dgnx.‌3adgnx3dgnx‌=‌−2x2+y3dgnx‌a=‌−2x2+y3dgnx answer :a=‌−2x2+y3dgnx

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shondagross2 shondagross2 · Answer 2 · 2020-11-06T22:50:15+01:00

shondagross2 shondagross2

06-11-2020

Let's solve for a.y=2x2+3andgxStep 1: Flip the equation.3adgnx+2x2=yStep 2: Add -2x^2 to both sides.3adgnx+2x2+−2x2=y+−2x23adgnx=−2x2+yStep 3: Divide both sides by 3dgnx.‌3adgnx3dgnx‌=‌−2x2+y3dgnx‌a=‌−2x2+y3dgnx answer :a=‌−2x2+y3dgnx

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f(x) = 2x^2 + 3 and g(x) = x^2 - 7, find (f-g)(x) A) 3x^2 - 10 B) x^2 - 4 C) x^2 + 10 D) 3x^2 - 4

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f(x) = 2x^2 + 3 and g(x) = x^2 - 7, find (f-g)(x)

A) 3x^2 - 10
B) x^2 - 4
C) x^2 + 10
D) 3x^2 - 4