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The wavelength of the characteristic, bright yellow-orange flame test color of sodium is 590 nm. Calculate the average energy (ΔE) associated with this atomic emission line.

Respuesta :

W0lf93
The energy associated with the 590nm atomic emission line is 3.369 x 10^49 Joules. This can be determined by multiplying Plank’s constant (6.626 x 10^34 Js) by the speed of light (3x 10^8 m/s), and then dividing the result by the wavelength (590 x 10^-9 m).