Respuesta :
[tex]\frac{8}{2+2i}=\\
\frac{8}{2+2i}*\frac{2-2i}{2-2i}=\\
\frac{16-16i}{4-4i^2}=\\
\frac{16-16i}{4+4}=\\
\frac{16-16i}{8}=\\
2-2i[/tex]
so it is the first option
so it is the first option