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Suppose you want to solve the equation 2a b=2a where a and b are nonZero real numbers describe the solution to this equation justify you description

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taskmasters
To solve this equation we can first assume that both a and b are nonzero real numbers. Hence, A = 1 b = 1
1.   2 (1) + 1 = 2(1)
2.    2 + 1 = 2: now this a false equation since there is not equality, the equation cannot retain the equal sign but will become 2 + 1 > 2. Leaving the relationship unequal.

However, the alternative to this problem is to be b = 0. To oversee the rule in order to solve the equation retaining it as an “equation”. Further, there is no other solution for this equation. A = 1 b = 0
1.   Which becomes 2(1) + 0 = 2(1)
2.    2 + 0 = 2 :
3.    2 = 2. Here we can observe the equality.



danielmaduroh

We have the following equation:

[tex] 2a+b=2a [/tex]

By solving this equation we have that:

[tex] 2a+b=2a \\ \\ \therefore (2a-2a)+b=0 \\ \\ \therefore \boxed{b=0} [/tex]

So, the only solution to this problem is [tex]b=0[/tex] for any real value of [tex]a[/tex]


Then, the conclusion is:

[tex]a \ is \ a \ nonzero \ real \ number \\ \\ b \ \mathbf{must} \ be \ zero[/tex]

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