Respuesta :
We know that,
Interest, I = [tex] \frac{P×R×T}{100} [/tex]
Where, P = Principal = $1300
R = rate of interest = 9% annually = [tex] \frac{9}{12} [/tex]%
T = Time = 1 month
So, I = [tex] \frac{1300×[tex] \frac{9}{12} [/tex]×1}{100} [/tex]
= $9.75
Interest paid per month is $9.75
Interest, I = [tex] \frac{P×R×T}{100} [/tex]
Where, P = Principal = $1300
R = rate of interest = 9% annually = [tex] \frac{9}{12} [/tex]%
T = Time = 1 month
So, I = [tex] \frac{1300×[tex] \frac{9}{12} [/tex]×1}{100} [/tex]
= $9.75
Interest paid per month is $9.75
Answer:
simple interest = $9.75
Step-by-step explanation:
given data:
Principle = $1300
annual rate = 9% [tex]= \frac{9}{`12} = 0.75 [/tex]
time = 6 year =
we knwo that simple interest is given as
Simple interest [tex]= \frac{P\times R\times T}{100}[/tex]
FOR ABOVE QUESTION
Time is 1 month
simple interest [tex]= \frac{1300\times 0.75 \times 1}{100}[/tex]
simple interest = $9.75