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How many permutations of three items can be selected from a group of six? use the letters a, b, c, d, e, and f to identify the items, and list each of the permutations of items b, d, and f?

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kachhadiyasatis
Number of permutations of 3 items can be selected from a group of 6 
 = 6P3
 = \frac{6!}{3!} 
 = \frac{6 x 5 x 4 x 3!}{3!} 
 = 6 x 5 x 4
 = 120

There are 120 permutations.

Permutations of items b, d and f is the different arrangement using these 3 letters & they are
bdf, bfd, dbf, dfb, fbd, fdb
adioabiola

The number of permutations of 6 items that can be selected from a group of 6 is; 120 ways.

List of permutations of items b,d and f is; bdf, bfd, dbf, dfb, fdb, fbd

Permutations and selection

The permutation required can be evaluated as follows;

  • 6P3

  • 6!/3!

  • 6× 5× 4 × 3!/3!

= 6×5×4 = 120 ways.

The List of permutations of items b,d and f is;

  • bdf
  • bfd
  • dbf
  • dfb
  • fdb
  • fbd

Read more on permutation;

https://brainly.com/question/12468032

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