The probability that a proofreader who catches 70% of the word errors misses exactly 7 out of 10 will be 0.3504.
It should be noted that this is a binomial distribution.
From the information given, the human proofreaders catch 70% of word errors and a student was asked to proofread an essay in which you have deliberately made 10 word errors.
Here, n = 10
p = 0.3,
q = 1 - 0.3 = 0.7.
The probability will be:
= 1 - (10C0 × 0.3ⁿ × 0.7^10 + 10C1 × 0.3 × 0.7^9 + 10C2 × 0.3² × 0.7^8 + 10C3 × 0.3³ × 0.7^7)
= 1 - 0.6496
= 0.3504
In conclusion, the probability is 0.3504.
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