First get the perimeter
Perimeter: 2l + 2w = 1064 yd
The region inside the fence is the area
Area: A = lw
We need to solve the perimeter formula for either length or width.
2l + 2w = 1064 yd
2w = 1064 yd – 2l
W = 1064– 2l / 2
W = 532 – l
Now substitute than to the area formula
A = lw
A = l (532 – l)
A = 532 – l^2
Since the equation A represents a quadratic expression, rewritte the expression with the exponents in descending order
A(l) = -l^2 + 532l
Then look for the value of the x coordinate
l = -b/2a
l = -532/2(-1)
l = -532/-2
l = 266 yards
Plugging in the value into our calculation for area:
A(l) = -l^2 + 532
A(266) = -(266)^2 + 532 (266)
A(266) = 70756+ 141512
= 70756 square yards.
Thus the largest area that could encompass would be a square where each side has a length of 266 yards and a width of:
W = 532 – l
= 532 – 266
= 266
It should be noted that the largest total area that can be enclosed will be 70756 yards².
Firstly, we have to calculate the perimeter. This will be:
2l + 2w = 1064 yd
Area: A = length × width
2l + 2w = 1064 yd
2w = 1064 yd – 2l
W = 1064– 2l / 2
W = 532 – l
Since Area = lw
A = l(532 – l)
A = 532 – l²
A(l) = -l² + 532l
l = -b/2a
l = -532/2(-1)
l = -532/-2
l = 266 yards
The length is 266 yards.
Area = -l² + 532
A( = -(266)² + 532 (266)
Area = 70756+ 141512
Area = 70756 yards²
Learn more about areas on:
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