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an object increases its velocity from 22m/s to 36 m/s in 5s. what is the acceleration of the object?

Respuesta :

mashteyman
The acceleration formula is Vf-Vi/2t or acceleration equals the final velocity minus the initial velocity divided by time.
The object's final velocity: 36 m/s
The objects initial velocity: 22 m/s
The time: 5 seconds
36-22/5
14/5
14/5=2.8
The acceleration of the object is 2.8 m/s^2.

Lanuel

The acceleration of the object is 2.8 [tex]m/s^2[/tex].

Given the following data:

  • Initial velocity = 22 m/s.
  • Final velocity = 36 m/s.
  • Time = 5 seconds.

To find the acceleration of the object:

Mathematically, acceleration is given by the formula;

[tex]A = \frac{V\; - \;U}{t}[/tex]

Where:

  • A is the acceleration.
  • V is the final velocity.
  • U is the initial velocity.
  • t is the time measured in seconds.

Substituting the parameters into the formula, we have;

[tex]A = \frac{36 \; - \;22}{5}\\\\A = \frac{14}{5}[/tex]

Acceleration, A = 2.8 [tex]m/s^2[/tex]

Therefore, the acceleration of the object is 2.8 [tex]m/s^2[/tex].

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