contestada

A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 32 square feet. Find the lengths of the sides of the poster and the sign?

Respuesta :

Area of square one = [tex](x-2)(x-2)[/tex] = [tex]x^2-4x+4[/tex]
Area of square two = [tex]x^2[/tex]

The difference of the area of two squares = 32
[tex]x^2-(x^2-4x+4)=32[/tex]
[tex]x^2-x^2+4x-4=32[/tex]
[tex]4x-4=32[/tex]
[tex]4x=32+4[/tex]
[tex]4x=36[/tex]
[tex]x=36/4[/tex]
[tex]x=9[/tex]

The side length of the poster = [tex]x-2 = 9-2 = 7 feet[/tex]
The side length of the sign = [tex]x=9[/tex]
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