The second side of a triangular deck is 3 feet longer than the shortest side and a third side that is 3 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 68 feet, what are the lengths of the three sides?

Respuesta :

The perimeter of a triangle is:

P = a + b + c

 

We are given that:

b = a + 3

c = 2 a – 3

 

Therefore:

68 = a + a + 3 + 2 a – 3

68 = 4 a

a = 17

 

and,

b = a + 3 = 20

c = 2a – 3 = 31

The shortest side of the triangle measures 17 feet.

The second side of the triangle measures 20 feet.

The third side of the triangle measures 31 feet.

What is the length of the three sides?

The perimeter of a triangle is the sum of the length of the three sides of the triangle.

Let the shortest side be represented with s.

The second side = 3 + s

The third side = 2s - 3

2s - 3 + 3 + s + s = 68

4s = 68

s = 17

The second side = 17 + 3 = 20

The third side = = (2 x 17) - 3 = 31

To learn more about triangles, please check: https://brainly.com/question/9329354