How much heat is needed to raise the temperature of 5.58 kilograms of iron from 20.0 Celsius to 1000.0 Celsius? Specific heat of iron is 450,000 J/(kgx Celsius).
Type the correct answer to 3 significant digits. If the answer has an exponent, type the number, then ^, then the exponent.

Respuesta :

  smaller                    bigger
Fraction             1/100  1/10
Decimal notation     0.01   0.1  1    10    100   1,000 ________________________________________________________Scientific notation  10-2   10-1  100  101   102   103 Here are some problems to make scientific notation more clear:Examples101 = 10   105 = 100,000   10–3 = 0.001   10–7 = 0.0000001
mass = m = 5.58 kg
specific heat index = c = 450000 J/(kg*C)
deltaT = change in temperature = 1000-20 = 980

Plug those three values into the formula below
Q = mc*(delta T)
Q = 5.58*450000*980
Q = 2,460,780,000

Rounding to three sig-figs, we will get the final answer to be 2,460,000,000
Note: this number is 2.46 billion (equivalent to 2 billion, 460 million)