Since it is specified that the relationship is linear, you could think of a linear graph for this. The base year would be 1994. The first point is at (0,2523) while the second point is (2,2891). The slope would be
m = (2891 - 2523)/(2-0) = 184
The slope-intercept form is y = mx + b. Let's substitute (0,2523) to the equation such that
2523 = 184(0)+b
b = 2523
Hence, the equation of the linear graph is y = 184x + 2523. Now, at 2006, x = 2006 - 1994 = 12 years.
y = 184(12) + 2523 = 4,731 students
