Respuesta :
A)[tex]R=0.65log(0.39E)+1.45
7.5=0.65log(0.39E)+1.45[/tex]
B)[tex]6.05=0.65log(0.39E) Subtracted 1.45 from~ both~ sides~ of~ equation. 9.31=log(0.39E) Divided each side by 0.65. [/tex]
C) [tex]9.31=log(0.39E) 10^(9.31)=0.39E E=5.24*10^9 kilowatt hours[/tex]
B)[tex]6.05=0.65log(0.39E) Subtracted 1.45 from~ both~ sides~ of~ equation. 9.31=log(0.39E) Divided each side by 0.65. [/tex]
C) [tex]9.31=log(0.39E) 10^(9.31)=0.39E E=5.24*10^9 kilowatt hours[/tex]
Amount of energy released during Earthquake is [tex]5.23*10^{6} kilowatt[/tex]
The Richter scale is used to measure the magnitude of a earthquake. The magnitude R is,
[tex]R=0.65log(0.39E)+1.45[/tex] E is the energy (measured in kilowatt-hours) released by the earthquake.
Given that, R = 7.5
Substituting the value of R into above equation.
[tex]7.5=0.65log(0.39E)+1.45\\\\7.5-1.45=0.65log(0.39E)\\\\6.05=0.65log(0.39E)\\\\9.31=log(0.39E)\\\\0.39E=10^{9.31}\\\\E=\frac{10^{9.31} }{0.39} \\\\E=5235225499watt\\\\E=5.23*10^{6} kilowatt[/tex]
Thus, Amount of energy released is [tex]5.23*10^{6} kilowatt[/tex]
Learn more about Earthquake here :
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