A ball is dropped off of a tall building and falls for 2 seconds before landing on a balcony. a rock is then dropped from the top of the building and falls for 4 seconds before landing on the ground. how does the final speed (meaning the speed it had just before landing) of the rock compare to the final speed of the ball?

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01-09-2017
Physics

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A ball is dropped off of a tall building and falls for 2 seconds before landing on a balcony. a rock is then dropped from the top of the building and falls for 4 seconds before landing on the ground. how does the final speed (meaning the speed it had just before landing) of the rock compare to the final speed of the ball?

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johnkellock johnkellock · Answer 1 · 2017-09-12T05:02:37+02:00

Using the formula Final speed = initial speed + gravity * time, we can compare the results.

Being gravity approximately 9.8 m/s^2, and being both the rock and the ball dropped, we can assume that the initial speed of both is zero, so:

Ball: 9.8m/s^2 * 2s = 18.6 m/s
Rock: 9.8 m/s^2 * 4 = 37.2 m/s

The speed of the rock is the double of the speed of the ball at the moment just before landing, because it has been dropped in a greater height than the ball, allowing the rock to reach a greater speed than the ball.