Practice Problems 13: 1. A spring is kept compressed by a toy car of mass 100 g. On releasing the spring the car moves out with a speed of 0.5 ms. Calculate the potential energy of the compressed spring. [0.025 J]

According to the law of conservation of energy, the total mechanical energy (sum of kinetic and potential energies) remains constant. Initially, all the energy is potential energy stored in the spring. After release, it becomes kinetic energy.

Therefore, we can say that the potential energy (U) of the compressed spring is equal to the kinetic energy (K) of the toy car: U = K

The formula for kinetic energy is given by the formula K = (1/2)mv², where:

m is the mass (kg)
v is the velocity (m/s)

We are given that m = 0.1 kg (100 g = 0.1 kg) and v = 0.5 m/s. Let's plug these values into the formula:

K = (1/2)(0.1)(0.5)²

K = 0.0125 J

Since the total potential energy is equal to the total kinetic energy, the potential energy of the compressed energy is also 0.0125 J.

The potential energy of the compressed spring is 0.0125 J.

Learn more about the law of conservation of energy here: https://brainly.com/question/166559

Practice Problems 13: 1. A spring is kept compressed by a toy car of mass 100 g. On releasing the spring the car moves out with a speed of 0.5 ms. Calculate the potential energy of the compressed spring. [0.025 J] ​

Respuesta :

The potential energy of the compressed spring is 0.0125 J.

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Practice Problems 13: 1. A spring is kept compressed by a toy car of mass 100 g. On releasing the spring the car moves out with a speed of 0.5 ms. Calculate the potential energy of the compressed spring. [0.025 J]