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A 100-kg box is placed on a conveyor belt. After traveling 12.0 m, the conveyor belt has accelerated the box to a speed of 5.00 m/s. What force is applied to the box by the conveyor belt to achieve this speed?

Respuesta :

audreyn06

Answer: 104.17 N

Explanation:

The formula for work (W) is given as:

W = Fd, where:

  • F is the force
  • d is the displacement

Work is also equal to the change in kinetic energy. The formula for kinetic energy (K) is given as:

K = (1/2)mv², where:

  • m is the mass
  • v is the velocity

We can set these two equations equal to each other:
W = K

Fd = (1/2)mv²

According to the problem, we are given the following values:

  • d = 12 m
  • m = 100 kg
  • v = 5 m/s

Let's substitute these values into the equation:

F(12) = (1/2)(100)(5²)

Solve for F:

F(12) = 1250

F ≈ 104.17 N

The force applied to the box by the conveyor belt to achieve this speed of 5 m/s is 104.17 N.

Learn more about work here: https://brainly.com/question/31343354

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