Answer:
(- 2, 3 )
Step-by-step explanation:
given the system of equations
x + 2y = 4 → (1)
- 2x - 1y = 1 → (2)
rearrange (1) by subtracting 2y from both sides
x = 4 - 2y
substitute x = 4 - 2y into (2)
- 2(4 - 2y) - y = 1 ← distribute parenthesis and simplify left side
- 8 + 4y - y = 1
- 8 + 3y = 1 ( add 8 to both sides )
3y = 9 ( divide both sides by 3 )
y = 3
substitute y = 3 into either of the 2 equations and solve for x
substituting into (1)
x + 2(3) = 4
x + 6 = 4 ( subtract 6 from both sides )
x = - 2
The solution is (- 2, 3 )