Answer:
With 1.75 moles of H2, approximately 139.11 grams of copper(II) oxide can be reduced to copper metal.
Explanation:
To determine how many grams of copper(II) oxide (CuO) can be reduced to copper metal (Cu) with 1.75 moles of H2, we need to use the stoichiometry of the balanced equation:
CuO + H2 = Cu + H2O
From the balanced equation, we can see that the molar ratio between CuO and H2 is 1:1. This means that for every 1 mole of CuO, we need 1 mole of H2 to completely reduce it.
Given that we have 1.75 moles of H2, we can conclude that we also need 1.75 moles of CuO to react with the H2.
To convert moles to grams, we need to know the molar mass of CuO. Copper has a molar mass of approximately 63.55 g/mol, and oxygen has a molar mass of approximately 16.00 g/mol.
The molar mass of CuO can be calculated as follows:
(1 atom of copper × molar mass of copper) + (1 atom of oxygen × molar mass of oxygen)
= (1 × 63.55 g/mol) + (1 × 16.00 g/mol)
= 63.55 g/mol + 16.00 g/mol
= 79.55 g/mol
Now we can calculate the grams of CuO using the following equation:
Grams of CuO = moles of CuO × molar mass of CuO
= 1.75 moles × 79.55 g/mol
= 139.11 grams
Therefore, with 1.75 moles of H2, approximately 139.11 grams of copper(II) oxide can be reduced to copper metal.
Answer:
139.2 grams CuO
Explanation:
The chemical equation is balanced. It tells us that 1 mole of H2 will react with 1 mole of CuO, a molar ratio of 1:1. 1.75 moles of CuO will completely react with the 1.75 moles of H2 that is present.
To find the number of grams this represents, multiply the moles by the molar mass of CuO.
Molar Mass of CuO = 79.55 g/mole
(1.75 moles CuO)*(=79.55 g/mole) = 139.2 grams CuO
