In the right triangle ΔABC with m∠C = 90°, m∠A = 75°, and AB= 12 cm. Find the area of ΔABC.
Please help!!!

Respuesta :

Answer:

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Step-by-step explanation:

Remember for RIGHT triangles such as this

S-O-H-C-A-H-T-O-A

SIN 75 = opposite / hypotenuse

sin 75 = BC / 12

12 sin 75° = BC    = 11.59 cm

COS 75 = adjacent / hypotenuse

cos 75° = AC/12

12 cos 75° = AC   = 3.11 cm

Now you have the base and the height

Area = 1/2 b * h

        = 1/2 11.59 * 3.11 = 18 cm^2