kay’s on is looking at two buildings, building A and building B at an angle of elevation of 73°. Building A is 30 feet away, and building B is 35 feet away. Which building is taller and by approximately how many feet

A) Building A it is around 16.35ft taller than building B

B) Building A is around 114.48ft taller than building B

C) Building B it is around 16.35ft taller than building A

D) Building B it is around 114.48ft taller than building A

Given that Kay's son is looking at building A and building B at an angle of elevation of 73°, and building A is 30 feet away while building B is 35 feet away, we can use the tangent function to find the heights of the buildings.

Let's define:

- hA as the height of building A

- hB as the height of building B

Using the tangent function, we have:

tan(73°) = hA / 30

tan(73°) = hB / 35

To find the heights, we can rearrange the equations:

hA = 30 * tan(73°)

hB = 35 * tan(73°)

Calculating these values, we get:

hA ≈ 30 * 3.6268604078470187 ≈ 108.80581223544157 feet

hB ≈ 35 * 3.6268604078470187 ≈ 127.04561278009415 feet

So, building B is taller than building A, and the height difference is approximately:

hB - hA ≈ 127.04561278009415 - 108.80581223544157 ≈ 18.24 feet.

Therefore, the correct answer is:

C) Building B is around 16.35 feet taller than building A.