Respuesta :
Answer:
1st Option is correct
Step-by-step explanation:
Since the SAS Postulate deals with 2 sides being equal and the angle between them being equal, BC=CD & AC is a common side, so, the angle between the sides is ∠BCA and ∠DCA
So, if AC⊥BD, ∠BCA=∠DCA
∴1st Option is correct
Answer:
[tex]\text{AC}\perp\text{BD}[/tex]
Explanation:
[tex]\text{If AC}\perp\text{BD}:\\\text{In triangles ABC and ADC,}\\\text{i. }\text{BC = CD (S)}\ \ \ [\text{Given}]\\\text{ii. }\angle \text{ACB = }\angle \text{ACD (A)}\ \ \ [\text{AC}\perp\text{BD}]\\\text{iii. }\text{AC = AC (S) [Common side]}\\\text{iv. }\triangle \text{ABC}\cong\triangle \text{ADC}\ \ \ [\text{By S.A.S. postulate}][/tex]