Explanation of the Question in the Image
Given individuals III-2 and I-1 are both females, we can conclude they are D. carriers. When discussing genetics, only women can be carriers because they have two sets of x-chromosomes (present in either xRxr, xRxR, or xrxr). These two sets allow women to be heterozygous, unlike males. In this case, individuals III-2 and I-1 are carriers because if they were homozygous, the entire circle either would be clear or shaded.
Explanation of Typed Question
Given hemophilia is a sex-linked recessive trait, we must identify the percent chance of attaining a recessive trait.
Individual I-1 has a genotype of homozygous dominant, while individual III-2 has a genotype of homozygous recessive. Therefore, the punnett square we would set up would consist of xry × xRxR.
Upon calculation through punnett squares, we will find that there is a 50% chance one of the children will display hemophilia.
