Barium peroxide is BaO2.
Hydrogen peroxide is H2O2
This reaction produces hydrogen peroxide from barium peroxide:
BaO2 + H2SO4 ---> BaSO4 + H2O2
So, 1 mol of BaO2 produces 1 mol of H2O2.
Convert 1.50 g of BaO2 to moles:
moles = mass in grams / molar mass
molar mass of BaO2 = 137g/mol + 2*16g/mol = 169 g/mol
moles of BaO2 = 1.50g / 169 g/mol = 0.00888 moles
Then, the same number, 0.00888, will be produced of H2O2.
Now convert 0.00888 moles of H2O2 to mass in grams:
mass in grams = number of moles * molar mass
molar mass of H2O2 = 2 * 1 g/mol + 2 * 16 g/mol = 34 g/mol
mass of H2O2 = 0.00888 moles * 34 g/mol = 0.30192 grams.
Rounded to 3 significant figures = 0.302 grams.
Answer: 0.302 grams
