This problem states that the sum of 3 consecutive integers is 63 and it asks us to find the largest integer.
Three consecutive integers can be represented as followed.
X → first integer
X + 1 → second integer
X + 2 → third integer
Since the sum of our three consecutive integers is 24, we can write an equation.
X + X + 1 + X + 2 = 63
We can simplify our equation on the left and it will read...
3x + 3 = 63
-3 -3
3x = 60
÷3 ÷3 ← divide both sides by 3
X = 20
Largest integer = X + 2
20 + 2 = 22
Largest integer = 22
