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If two fair dice areâ rolled, find the probability that the sum of the dice is 10â, given that the sum is greater than 8.

Respuesta :

If the sum is greater than 8, it can be 9, 10, 11 or 12.

sum 9: 6+3, 3+6, 5+4, 4+5, 4 cases
sum 10: 4+6, 6+4, 5+5, 3 cases
sum 11: 5+6, 6+5, 2 cases
sum 12: 6+6, 1 case

so P(sum 10/ sum>8) = 3 / (4+3+2+1) = 3/10

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