Respuesta :
1.
When a line is given in the form y=mx+n,
m is the slope of this line.
For example, the slope of the line y=-2x+7 is -2.
2.
If lines y=mx+n and y=kx+t are perpendicular, then the multiplication of their slopes is -1, that is
m*k = -1, so k=-1/m
3.
any line perpendicular to y=-2x+7 has slope = -1/(-2)=1/2
4.
Among the choices, y=(1/2)x-3 is a line perpendicular to the given line.
Answer:
b. y=(1/2)x-3
When a line is given in the form y=mx+n,
m is the slope of this line.
For example, the slope of the line y=-2x+7 is -2.
2.
If lines y=mx+n and y=kx+t are perpendicular, then the multiplication of their slopes is -1, that is
m*k = -1, so k=-1/m
3.
any line perpendicular to y=-2x+7 has slope = -1/(-2)=1/2
4.
Among the choices, y=(1/2)x-3 is a line perpendicular to the given line.
Answer:
b. y=(1/2)x-3
Answer:
[tex]y=\frac{1}{2} x-3[/tex]
Step-by-step explanation:
Step 1
Find the slope of the line EF
we have
[tex]y=-2x+7[/tex]
The slope of the line EF is equal to
[tex]m=-2[/tex]
Step 2
Find the slope of the line perpendicular to the line EF
we know that
If two lines are perpendicular, then the product of its slopes is equal to minus one
so
[tex]m1*m2=-1[/tex]
we have
[tex]m1=-2[/tex] -----> slope of the line EF
Find the value of m2
substitute
[tex](-2)*m2=-1[/tex]
[tex]m2=1/2[/tex]
therefore
the equation [tex]y=\frac{1}{2} x-3[/tex] could be an equation for a line that is perpendicular to line EF