Answer:
We are given,
The transformed function is [tex]f(x)=\sqrt{x+1}-5[/tex].
So, we can see that,
The parent function is [tex]f(x)=\sqrt{x}[/tex].
Then, we have,
The parent function is translated 1 units to the left to give [tex]\sqrt{x+1}[/tex].
Then, it is translated 5 units downwards to give the function [tex]\sqrt{x+1}-5[/tex].
Hence, we have,
The parent function f(x) = √x has been shifted 1 unit left and 5 units down
The parent function of a square root function is represented as:
[tex]f(x) = \sqrt x[/tex]
When the function is shifted 1 unit left, we have the following equation
[tex]f(x) = \sqrt {x + 1}[/tex]
When the function is shifted 5 units down, we have the following equation
[tex]f(x) = \sqrt {x + 1} - 5[/tex]
Hence, the parent function f(x) = √x has been shifted 1 unit left and 5 units down
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