EASY 5 POINTS!!! You want to help build an awards podium for a track meet. If the podium has the dimensions shown, what is its volume?

EASY 5 POINTS You want to help build an awards podium for a track meet If the podium has the dimensions shown what is its volume class=

Respuesta :

Answer:

The volume is equal to [tex]18\ cm^{3}[/tex]

Step-by-step explanation:

we know that

The volume of each figure is equal to

[tex]V=LWH[/tex]

where

L is the length

W is the width

H is the height

Step 1

Find the volume of figure N 1

[tex]V1=1.5*2*3=9\ cm^{3}[/tex]

Step 2

Find the volume of figure N 2

[tex]V2=1.5*2*2=6\ cm^{3}[/tex]

Step 3

Find the volume of figure N 3

[tex]V3=1.5*2*1=3\ cm^{3}[/tex]

Step 4

Find the total volume

[tex]V=V1+V2+V3=9+6+3=18\ cm^{3}[/tex]

Answer:

[tex]\text{Volume of podium}=18\text{ ft}^3[/tex]

Step-by-step explanation:

We have been given a graph of podium for a track meet and we are asked to find the volume of our given podium.

To find the volume of podium we will find volume of each podium using volume of cuboid formula.

[tex]\text{Volume of cuboid}=l*b*h[/tex], where,

[tex]l=\text{ Length of cuboid}[/tex],

[tex]b=\text{ Breadth of cuboid}[/tex],

[tex]h=\text{ Height of cuboid}[/tex].

Upon substituting our given values in cuboid formula we will get,

[tex]\text{Volume of cuboid 1}=\text{3 ft*2 ft*1.5 ft}[/tex]    

[tex]\text{Volume of cuboid 1}=9\text{ ft}^3[/tex]    

[tex]\text{Volume of cuboid 2}=\text{2 ft*2 ft *1.5 ft}[/tex]

[tex]\text{Volume of cuboid 2}=6\text{ ft}^3[/tex]

[tex]\text{Volume of cuboid 3}=\text{1 ft*2 ft *1.5 ft}[/tex]

[tex]\text{Volume of cuboid 3}=6\text{ ft}^3[/tex]

Let us add volume of each cuboid to find the volume of our given podium.

[tex]\text{Volume of podium}=9\text{ ft}^3+6\text{ ft}^3+3\text{ ft}^3[/tex]

[tex]\text{Volume of podium}=18\text{ ft}^3[/tex]

Therefore, volume of our given podium is 18 cubic feet.