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Ashton, Bryan and Charles were given the same number of funfair tickets to sell. Charles sold 92 tickets. Bryan had twice as many tickets left unsold as Ashton's. Charles number of tickets left unsold was 14 fewer than Bryan's. There was a total of 491 unsold tickets. How many tickets did each of them have to sell? ​

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Hi1315

Answer:

Ashton - 101

Bryan - 202

Charles - 188

Step-by-step explanation:

Let's denote the number of tickets Ashton had to sell as A.

Given:

1. Charles sold 92 tickets.

2. Bryan had twice as many tickets left unsold as Ashton's.

  So, Bryan had 2A tickets left unsold.

3. Charles had 14 fewer unsold tickets than Bryan.

  Charles had 2A - 14 tickets left unsold.

4. The total number of unsold tickets was 491.

From the information provided, we can create an equation to represent the total number of unsold tickets:

A  + 2A  + (2A - 14) = 491

Solving the equation:

A + 2A + 2A - 14 = 491

5A - 14 = 491

5A = 505

A = 101

Ashton had 101 tickets to sell.

Bryan had 2 × 101 = 202 tickets left unsold.

Charles had 2 × 101 - 14 = 202 - 14 = 188 tickets left unsold.

Answer:

Ashton-101

Bryan-202

Charles-188

Step-by-step explanation:

1. Charles sold 92 tickets.

2. Bryan had twice as many tickets left unsold as Ashton's. So, Bryan had 2A tickets left unsold.

3. Charles had 14 fewer unsold tickets than Bryan. Charles had 2A - 14 tickets left unsold.

4. The total number of unsold tickets was 491.

From the information provided, we can create an equation to represent the total number of unsold tickets:

A + 2A + (2A - 14) = 491

Solving the equation:

A + 2A + 2A - 14 = 491

5A - 14 = 491

5A = 505

A = 101

Therefore, Ashton had 101 tickets to sell.

Bryan had 2 × 101 = 202 tickets left unsold.

Charles had 2 × 101 - 14 = 202 - 14 = 188 tickets left unsold.

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