Respuesta :
ANSWER
A. True
EXPLANATION
Let
[tex](x_1,y_1) = (1,2)[/tex]
and
[tex](x_2,y_2) = (2,3)[/tex]
be two points on the straight line.
Then the slope is given by
[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]
This implies that,
[tex]m = \frac{3 - 2}{2 - 1} = \frac{1}{1} = 1[/tex]
Let us now choose it the other way round,
[tex](x_1,y_1) = (2,3)[/tex]
[tex](x_2,y_2) = (1,2)[/tex]
Then the slope is,
[tex]m = \frac{2 - 3}{1 - 2} = \frac{ - 1}{ - 1} = 1[/tex]
We still had they same result. Hence it doesn't matter which one you choose to call
[tex](x_1,y_1)[/tex]
and which to call
[tex](x_2,y_2) [/tex]
A. True
EXPLANATION
Let
[tex](x_1,y_1) = (1,2)[/tex]
and
[tex](x_2,y_2) = (2,3)[/tex]
be two points on the straight line.
Then the slope is given by
[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]
This implies that,
[tex]m = \frac{3 - 2}{2 - 1} = \frac{1}{1} = 1[/tex]
Let us now choose it the other way round,
[tex](x_1,y_1) = (2,3)[/tex]
[tex](x_2,y_2) = (1,2)[/tex]
Then the slope is,
[tex]m = \frac{2 - 3}{1 - 2} = \frac{ - 1}{ - 1} = 1[/tex]
We still had they same result. Hence it doesn't matter which one you choose to call
[tex](x_1,y_1)[/tex]
and which to call
[tex](x_2,y_2) [/tex]