Respuesta :
Answer:
Step-by-step explanation:
Given that A cone is placed inside a cylinder. The cone has half the radius of the cylinder, but the height of each figure is the same
Whatever position cone is placed, the space remaining will have volume as
volume of the cylinder - volume of the cone
Let radius of cylinder be r and height be h
Then volume of cylinder = [tex]\pi r^2 h[/tex]
The cone has height as h and radius as r/2
So volume of cone = [tex]\frac{1}{3} \pi (\frac{r}{2} )^2h\\=(\pi r^2 h)\frac{1}{24}[/tex]
the volume of the space remaining in the cylinder after the cone is placed inside it
=[tex]\pi r^2 h (1-\frac{1}{24} )\\=\frac{23 \pi r^2 h}{24}[/tex]
