Answer:
7 times during the first 15 minutes
Step-by-step explanation:
Remember that
[tex]1\ min=60\ sec[/tex]
so
[tex]15\ min=15(60)=900\ sec[/tex]
Decompose the numbers 18 and 42 in prime factors
we know that
[tex]18=(2)(3^2)[/tex]
[tex]42=(2)(3)(7)[/tex]
Find the least common multiple (LCM)
The LCM is
[tex](2)(3^2)(7)=126\ sec[/tex]
we need to find all multiples of 126 that are less than or equal 900.
[tex]126*1=126\ sec\\126*2=252\ sec\\126*3=378\ sec\\126*4=504\ sec\\126*5=630\ sec\\126*6=756\ sec\\126*7=882\ sec[/tex]
therefore
7 times during the first 15 minutes