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What is the distance between the points (22, 27) and (2, -10)? if necessary, round your answer to two decimal places.a. 57 units?

Respuesta :

texaschic101
distance formula : sqrt (x2 - x1)^2 + (y2 - y1)^2
(22,27)....x1 = 22 and y1 = 27
(2,-10)....x2 = 2 and y2 = -10
now we sub
d = sqrt (2 - 22)^2 + (-10 -27)^2)
d = sqrt (-20^2) + (-37^2)
d = sqrt (400 + 1369)
d = sqrt 1769
d = 42.06 <==
isyllus

Answer:

42.06

Step-by-step explanation:

Two points (22,27) and (2,-10)

using distance formula:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

So, distance between (22,27) and (2,-10) is D

[tex]D=\sqrt{(22-2)^2+(27-(-10))^2}[/tex]

[tex]D=\sqrt{(20)^2+(37)^2}[/tex]

[tex]D=\sqrt{400+1369}[/tex]

[tex]D=\sqrt{1769}[/tex]

[tex]D=42.059[/tex]

Round off two decimal place.

[tex]D=42.06[/tex]

Hence, The distance between the points is 42.06

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