Answer: The positive number is [tex]\dfrac{1}{2}.[/tex]
Step-by-step explanation: We are given to find the positive number that is twice it's own square.
Let x denotes the required number.
Then, according to the given information, we have
[tex]x=2x^2\\\\\Rightarrow 2x^2-x=0\\\\\Rightarrow x(2x-1)=0\\\\\Rightarrow x=0,~~2x-1=0\\\\\Rightarrow x=0,~\dfrac{1}{2}.[/tex]
Sine 0 is not considered as a positive number, so the required positive number is [tex]\dfrac{1}{2}.[/tex]
Thus, the positive number is [tex]\dfrac{1}{2}.[/tex]
