How many grams of (nh4)3po4 are needed to make 0.250 l of 0.150 m (nh4)3po4? hints how many grams of (nh4)3po4 are needed to make 0.250 l of 0.150 m (nh4)3po4? 5.47 g 5.59 g 89.5 g 2.52 x 10-4 g?

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04-07-2017
Chemistry

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How many grams of (nh4)3po4 are needed to make 0.250 l of 0.150 m (nh4)3po4? hints how many grams of (nh4)3po4 are needed to make 0.250 l of 0.150 m (nh4)3po4? 5.47 g 5.59 g 89.5 g 2.52 x 10-4 g?

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Аноним Аноним · Answer 1 · 2017-07-15T03:07:16+02:00

There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We calculate the mass of the solute by first determining the number of moles needed. And by using the molar mass, we can convert it to units of mass.

Moles (nh4)3po4 = 0.250 L (0.150 M) = 0.0375 moles (nh4)3po4
Mass = 0.0375 mol (nh4)3po4 (149.0867 g / mol) = 5.59 g (nh4)3po4