Given:
The sample array is
x = [123.6 123.9 123.9 123.7 123.4 123.3 123.3 123.6 123.5 123.9 123.5 123.7 124.4 123.7 123.9 124.0 124.2 123.7 123.8 123.8 124.0 123.9 123.6 124.2 123.4 123.4 123.4 123.4 123.3 123.7
123.5 123.6 124.2 123.9 123.9 123.8 123.9 123.7 123.8 123.8]
From the calculator,
The sample size is
n = 40
The sample mean is
xavg = 123.73
The sample std. deviation is
s = 0.27
The expected population average is
μ = 120
Calculate the test statistic.
z = (xavg - μ)/(s/√n) .
= (123.73 - 120)/(0.27/√40)
= 87.36
The null hypothesis is
H₀: xavg = μ
and the alternate hypothesis is
xavg > μ
At α=0.01 level of significance, the one-tailed test has a rejection region of
α/2 = 0.005.
From standard tables, the test statistic clearly falls in the rejection region.
We should reject the null hypothesis and conclude that xavg > μ.
Answer:
The claim that the mean voltage is 120 V is false at the 0.01 significance level.